answered 2-mandatory-debugs. 2.js

Author: leerogerfn

Sprint-3/2-mandatory-debug/0.js

@@ -1,7 +1,7 @@
 // Predict and explain first...
 
 // =============> write your prediction here
-// local scope code did not return to global.
+// A: The result of multiplying 10 and 32 is 320. But local scope code did not return to global.
 
 //function multiply(a, b) {
 //  console.log(a * b);
@@ -10,7 +10,7 @@
 //console.log(`The result of multiplying 10 and 32 is ${multiply(10, 32)}`);
 
 // =============> write your explanation here
-// The calculation of the a * b should apply the the statement (`The result of multiplying 10 and 32 is ${multiply(10, 32)}`).
+// A: The calculation of the a * b should apply the the statement (`The result of multiplying 10 and 32 is ${multiply(10, 32)}`).
 // because code on local scope did not return to global. The global cannot apply the result of local.
 
 // Finally, correct the code to fix the problem

Sprint-3/2-mandatory-debug/1.js

@@ -1,6 +1,6 @@
 // Predict and explain first...
 //  =============> write your prediction here
-// The result of the function supposed to print 'The sum of 10 and 32 is 42' local scope should be return to sum.
+// A: The result of the function supposed to print 'The sum of 10 and 32 is 42' local scope should be return to sum.
 
 //function sum(a, b) {
 //  return;
@@ -10,7 +10,7 @@
 console.log(`The sum of 10 and 32 is ${sum(10, 32)}`);
 
 // =============> write your explanation here
-// the answer is undefined because of local scope code did not return to global (sum). semicolon of return need to be removed.
+// A: the answer is undefined because of local scope code did not return to global (sum). semicolon of return need to be removed.
 // Finally, correct the code to fix the problem
 //  =============> write your new code here
 function sum(a, b) {

Sprint-3/2-mandatory-debug/2.js

@@ -2,23 +2,44 @@
 
 // Predict the output of the following code:
 // =============> Write your prediction here
+// A: The function supposed to print the last digit of 42, 105 and 806 which is 2, 5, 6. But the function could not run smooth
+// because of the variable "num" has been declared.
 
-const num = 103;
+//const num = 103;
 
-function getLastDigit() {
-  return num.toString().slice(-1);
-}
+//function getLastDigit() {
+//  return num.toString().slice(-1);
+//}
 
-console.log(`The last digit of 42 is ${getLastDigit(42)}`);
-console.log(`The last digit of 105 is ${getLastDigit(105)}`);
-console.log(`The last digit of 806 is ${getLastDigit(806)}`);
+//console.log(`The last digit of 42 is ${getLastDigit(42)}`);
+//console.log(`The last digit of 105 is ${getLastDigit(105)}`);
+//console.log(`The last digit of 806 is ${getLastDigit(806)}`);
+
+// This program should tell the user the last digit of each number.
+// Explain why getLastDigit is not working properly - correct the problem
 
 // Now run the code and compare the output to your prediction
 // =============> write the output here
+//A: The last digit of 42 is 3
+//The last digit of 105 is 3
+//The last digit of 806 is 3
+
 // Explain why the output is the way it is
 // =============> write your explanation here
+// A: because num has been declared for 103 so the function could only get the last digit of 42, 105 and 806.
+
 // Finally, correct the code to fix the problem
 // =============> write your new code here
 
+function getLastDigit(number) {
+  return number.toString().slice(-1);
+}
+
+console.log(`The last digit of 42 is ${getLastDigit(42)}`);
+console.log(`The last digit of 105 is ${getLastDigit(105)}`);
+console.log(`The last digit of 806 is ${getLastDigit(806)}`);
+
 // This program should tell the user the last digit of each number.
 // Explain why getLastDigit is not working properly - correct the problem
+// A: it is because num has been strictly declared as 103 before. and the value is console log could be be applied to function.
+// To fix this parameter of getLastDigit should assign for val as a placeholder to allow different value