Complete Sprint-3 debug exercises (0.js, 1.js, 2.js)

Author: lwandogwele52-ui

Sprint-3/2-mandatory-debug/0.js

@@ -1,14 +1,26 @@
 // Predict and explain first...
-
-// =============> write your prediction here
+//  ==============> write your prediction here
+// I predict this will run without an error, but print the wrong result at
+// the end. The 'multiply' function uses console.log internally instead of
+// returning a value, so when it's used inside the template literal, it will
+// show as 'undefined' instead of the actual multiplication result.
 
 function multiply(a, b) {
-  console.log(a * b);
+  return a * b;
 }
 
 console.log(`The result of multiplying 10 and 32 is ${multiply(10, 32)}`);
 
-// =============> write your explanation here
+// ==============> write your explanation here
+// The original 'multiply' function printed the result with console.log
+// instead of returning it. A function that doesn't explicitly return a value
+// returns 'undefined' by default. When the outer console.log tried to use
+// multiply(10, 32) inside the template literal, it inserted 'undefined'
+// instead of the actual number, because it was using the function's return
+// value, not what it printed internally. Changing console.log to return
+// inside the function fixes this, since now the function actually hands
+// back the calculated value.
 
 // Finally, correct the code to fix the problem
-//  =============> write your new code here
+// ==============> write your new code here
+// (the fixed function above already satisfies this)

Sprint-3/2-mandatory-debug/1.js

@@ -1,13 +1,27 @@
 // Predict and explain first...
-//  =============> write your prediction here
+//  ==============> write your prediction here
+// I predict this will run without an error, but the result will show as
+// 'undefined' instead of the actual sum. The 'return' statement is on its
+// own line, separate from 'a + b;' on the next line — JavaScript will treat
+// these as two separate statements, so the function returns immediately
+// with nothing, and 'a + b' never actually gets returned.
 
 function sum(a, b) {
-  return;
-  a + b;
+  return a + b;
 }
 
 console.log(`The sum of 10 and 32 is ${sum(10, 32)}`);
 
-// =============> write your explanation here
+// ==============> write your explanation here
+// JavaScript has a feature called Automatic Semicolon Insertion (ASI). When
+// 'return' appears on its own line with nothing after it, JavaScript
+// automatically treats it as 'return;' — ending the function right there and
+// returning 'undefined'. The following line, 'a + b;', becomes dead code
+// that never runs, because the function has already exited. This is why the
+// original code always produced 'undefined' instead of the sum. The fix is
+// to put the expression on the same line as 'return', so JavaScript knows
+// it's part of the return statement: 'return a + b;'.
+
 // Finally, correct the code to fix the problem
-//  =============> write your new code here
+// ==============> write your new code here
+// (the fixed function above already satisfies this)

Sprint-3/2-mandatory-debug/2.js

@@ -1,7 +1,11 @@
 // Predict and explain first...
 
 // Predict the output of the following code:
-// =============> Write your prediction here
+//  ==============> write your prediction here
+// I predict every call to getLastDigit will return the same result: "3",
+// no matter what number is passed in. This is because the function doesn't
+// take any parameters — it always uses the outer 'num' variable (103)
+// instead of the value passed into the function call.
 
 const num = 103;
 
@@ -14,11 +18,13 @@ console.log(`The last digit of 105 is ${getLastDigit(105)}`);
 console.log(`The last digit of 806 is ${getLastDigit(806)}`);
 
 // Now run the code and compare the output to your prediction
-// =============> write the output here
-// Explain why the output is the way it is
-// =============> write your explanation here
-// Finally, correct the code to fix the problem
-// =============> write your new code here
+//  ==============> write the output here
+// The last digit of 42 is 3
+// The last digit of 105 is 3
+// The last digit of 806 is 3
 
-// This program should tell the user the last digit of each number.
-// Explain why getLastDigit is not working properly - correct the problem
+// Explain why the output is the way it is
+//  ==============> write your explanation here
+// The function getLastDigit() is defined with no parameters, so the values
+// 42, 105, and 806 passed into each call are simply ignored — they go
+// nowhere. Instead, the